The probability that A speaks truth is 4/5, while this probability for B is 3/4. The probability that they contradict each other when asked to speak o - Mathematics MCQ AIEEE 2004 2026 | ExamTest.live

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The probability that A speaks truth is \frac{4}{5}, while this probability for B is \frac{3}{4} . The probability that they contradict each other when asked to speak on a fact is

Solution & Step-by-step Explanation

Let P (A) be the probability that A speaks the truth = 4/5 \Rightarrow P (A^{c}) = 1/5 . Let P (B) be the probability that B speaks the truth = 3/4 \Rightarrow P (B^{c}) = 1/4 . Contradiction occurs if one speaks the truth and the other lies. P (contradiction) = P (A \cap B^{c}) + P (A^{c} \cap B) . P (contradiction) = (4/5 \times 1/4) + (1/5 \times 3/4) = 4/20 + 3/20 = 7/20 .

Try it yourself before checking the explanation above.

The probability that A speaks truth is \frac{4}{5}, while this probability for B is \frac{3}{4} . The probability that they contradict each other when asked to speak on a fact is

\frac{3}{20}

\frac{1}{5}

\frac{7}{20}

\frac{4}{5}

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