The radius of a solid sphere is $R\text{cm}$. If it is bisected into two identical hemispheres, then the total surface area of the two pieces obtained is:

The total surface area of a solid sphere of radius $R$ is given by:
$$A_{\text{original}}=4\pi R^2$$

When the sphere is bisected, it forms two hemispheres. Each hemisphere exposes a new flat circular cross-sectional base with an area of $\pi R^2$.
The total surface area of a single solid hemisphere is:

$$A_{\text{hemi}}=\text{Curved Surface Area}+\text{Base Area}=2\pi R^2+\pi R^2=3\pi R^2$$

Since there are two pieces, the total combined surface area is:

$$\text{Total Surface Area}=2\times 3\pi R^2=6\pi R^2\text{sq.cm}$$