The ratio of wavelengths of the last line of Balmer series and the last line of Lyman series is: - Physics MCQ NEET 2017 2026 | ExamTest.live | ExamTest.live

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The ratio of wavelengths of the last line of Balmer series and the last line of Lyman series is:

A $2$
B $1$
C $4$
D $0.5$

Solution & Step-by-step Explanation

The last line (series limit) corresponds to n_{2} = \infty .Balmer series limit (n_{1} = 2): \frac{1}{λ _{B}} = R [\frac{1}{2 ^{2}} - \frac{1}{\infty ^{2}}] = \frac{R}{4} ⟹ λ_{B} = \frac{4}{R} .Lyman series limit (n_{1} = 1): \frac{1}{λ _{L}} = R [\frac{1}{1 ^{2}} - \frac{1}{\infty ^{2}}] = R ⟹ λ_{L} = \frac{1}{R} .Ratio \frac{λ _{B}}{λ _{L}} = \frac{4/ R}{1/ R} = 4 .

Practice this question

Try it yourself before checking the explanation above.

The ratio of wavelengths of the last line of Balmer series and the last line of Lyman series is:

A

2

B

1

C

4

D

0.5

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