The remainder left out when 8^2n - (62)^2n+1 is divided by 9 is: - Mathematics MCQ AIEEE 2009 2026 | ExamTest.live

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The remainder left out when 8^{2 n} - (62)^{2 n + 1} is divided by 9 is:

Solution & Step-by-step Explanation

8 \equiv - 1 (mod 9) ⟹ 8^{2 n} \equiv (- 1)^{2 n} \equiv 1 (mod 9) . 62 \equiv - 1 (mod 9) ⟹ (62)^{2 n + 1} \equiv (- 1)^{2 n + 1} \equiv - 1 (mod 9) .Expression \equiv 1 - (- 1) \equiv 2 (mod 9) .Remainder is 2 .

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The remainder left out when 8^{2 n} - (62)^{2 n + 1} is divided by 9 is:

0

2

7

8

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