The resultant of two forces and is a force of . If the direction of force were reversed, the resultant would be . The value of is:
- A
- B
- C
- D
Solution & Step-by-step Explanation

Let the angle between and be .Resultant . $
3\,\text{N} 180^\circ - \theta (\sqrt{19})^2 = P^2 + 3^2 + 2(P)(3) \cos(180^\circ - \theta)
$19 = P^2 + 9 - 6P \cos\theta \implies 10 = P^2 - 6P \cos\theta \dots(2)
Adding (1) and (2):