The smallest number, which multiplies to to get a perfect cube, is
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Solution & Step-by-step Explanation
1. Find the prime factorization of :
For a number to be a perfect cube, the exponents of all its prime factors must be multiples of 3.In the factorization , the prime factor 11 forms a perfect triplet (), but the prime factor 5 only has a power of 2 (). To form a triplet (), we need to multiply by one more 5.Therefore, the smallest number required is 5.
For a number to be a perfect cube, the exponents of all its prime factors must be multiples of 3.In the factorization , the prime factor 11 forms a perfect triplet (), but the prime factor 5 only has a power of 2 (). To form a triplet (), we need to multiply by one more 5.Therefore, the smallest number required is 5.