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The smallest perfect square number divisible by each of 6 and 12 is:

  1. A
    108
  2. B
    36
  3. C
    196
  4. D
    144

Solution & Step-by-step Explanation

To find the smallest perfect square divisible by both 6 and 12:
Find the LCM of 6 and 12:
The Least Common Multiple (LCM) of 6 and 12 is 12.
Any number divisible by both 6 and 12 must be a multiple of 12.

Find the prime factorization of 12:

12=2×2×3=2
2
×3
1

Make it a perfect square:
For a number to be a perfect square, the exponents of all its prime factors must be even numbers.
To make 12 a perfect square, we must multiply it by the missing factor to complete the pairs, which is 3:

Smallest perfect square=12×3=36
Checking the options, 36 is a perfect square (6
2
) and is perfectly divisible by both 6 and 12.

Practice this question

Try it yourself before checking the explanation above.

The smallest perfect square number divisible by each of 6 and 12 is:
A
108
B
36
C
196
D
144

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