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The submerged portion of a piece of pure ice floating in water is approximately:

  1. A
    of its volume.
  2. B
    of its volume.
  3. C
    of its volume.
  4. D
    of its volume.

Solution & Step-by-step Explanation

According to Archimedes' principle and the law of floatation, the fraction of the volume of a floating body that is submerged inside a liquid is given by the ratio of the density of the floating body to the density of the liquid:


The density of pure ice () is approximately and the density of pure water () is .



Expressing this fraction as a standard ratio approximation gives:



Thus, about of the ice volume stays completely submerged beneath the surface of the water.

Practice this question

Try it yourself before checking the explanation above.

The submerged portion of a piece of pure ice floating in water is approximately:
A
of its volume.
B
of its volume.
C
of its volume.
D
of its volume.

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