The sum of three numbers is 118. If the ratio of the first number to the second number is 3:4 and that of the second number to the third number is 5:6. Find the third number.
- A30
- B58
- C48
- D40
Solution & Step-by-step Explanation
Let the three numbers be A, B, and C.
Given ratios:
A:B=3:4
B:C=5:6
To combine the ratios, make the value of B same in both ratios by taking the LCM of 4 and 5, which is 20:
A:B=(3×5):(4×5)=15:20
B:C=(5×4):(6×4)=20:24
Thus, the combined ratio is:
A:B:C=15:20:24
Let the numbers be 15x, 20x, and 24x.
Their sum is given as 118:
15x+20x+24x=118
59x=118
x=
59
118
=2
Therefore, the third number (C) is:
C=24x=24×2=48
Given ratios:
A:B=3:4
B:C=5:6
To combine the ratios, make the value of B same in both ratios by taking the LCM of 4 and 5, which is 20:
A:B=(3×5):(4×5)=15:20
B:C=(5×4):(6×4)=20:24
Thus, the combined ratio is:
A:B:C=15:20:24
Let the numbers be 15x, 20x, and 24x.
Their sum is given as 118:
15x+20x+24x=118
59x=118
x=
59
118
=2
Therefore, the third number (C) is:
C=24x=24×2=48