The sum of two numbers is $80$ and their difference is $8$. What is the ratio of the two numbers?

Let the two numbers be $x$ and $y$ ($x>y$).According to the problem:$x+y=80$$x-y=8$ Adding the two equations:
$$2x=88⟹x=44$$
Subtracting the second equation from the first:
$$2y=72⟹y=36$$
The ratio of the two numbers is:
$$\frac{x}{y}=\frac{44}{36}=\frac{11}{9}$$