The terminal voltage of the battery, whose emf is 10 V and internal resistance 1 Ω , when connected through an external resistance of 4 Ω as shown in - Physics MCQ NEET (UG) 2024 2026 | ExamTest.live

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The terminal voltage of the battery, whose emf is 10 V and internal resistance 1 Ω, when connected through an external resistance of 4 Ω as shown in the figure, is:

Solution & Step-by-step Explanation

First, calculate the current (I) flowing in the circuit: I = \frac{E}{R + r} = \frac{10}{4 + 1} = \frac{10}{5} = 2 A The terminal voltage (V) is given by: V = E - I r V = 10 - (2 \times 1) = 8 V Alternatively, V = I R = 2 \times 4 = 8 V .

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The terminal voltage of the battery, whose emf is 10 V and internal resistance 1 Ω, when connected through an external resistance of 4 Ω as shown in the figure, is:

4 V

6 V

8 V

10 V

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