The value of $[9.5÷(0.6\times 0.75+0.8÷16)+0.75]÷(0.03÷0.6\text{ of }0.01)$ lies between:

Let us solve the expression step-by-step using BODMAS rules.Part 1: Simplifying the numerator/first main bracket
$$\text{Inner brackets first: }(0.6\times 0.75+0.8÷16)$$
$0.6\times 0.75=0.45$$0.8÷16=\frac{0.8}{16}=0.05$ Summing them up = $0.45+0.05=0.5$ Now substitute back into the bracket:
$$9.5÷0.5+0.75$$
$9.5÷0.5=19$$19+0.75=19.75$ Part 2: Simplifying the denominator/second main bracket
$$(0.03÷0.6\text{ of }0.01)$$
First evaluate 'of': $0.6\times 0.01=0.006$ Next perform division: $0.03÷0.006=\frac{0.03}{0.006}=\frac{30}{6}=5$ Part 3: Final division
$$\text{Final expression}=19.75÷5=3.95$$
The value $3.95$ lies between $3$ and $4$.