The wavelength of the radiation emitted, when in a hydrogen atom an electron falls from infinity to stationary state 1 , would be (Rydberg constant R - Chemistry MCQ AIEEE 2004 2026 | ExamTest.live

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The wavelength of the radiation emitted, when in a hydrogen atom an electron falls from infinity to stationary state 1, would be (Rydberg constant R = 1.097 \times 1 0^{7} m^{- 1}):

Solution & Step-by-step Explanation

Using the Rydberg formula: \frac{1}{λ} = R (\frac{1}{n _{1}^{2}} - \frac{1}{n _{2}^{2}}) . Given n_{1} = 1 and n_{2} = \infty : \frac{1}{λ} = 1.097 \times 1 0^{7} (\frac{1}{1 ^{2}} - \frac{1}{\infty ^{2}}) = 1.097 \times 1 0^{7} m^{- 1} . λ = \frac{1}{1.097 \times 1 0 ^{7}} m \approx 9.11 \times 1 0^{- 8} m = 91.1 nm .

Try it yourself before checking the explanation above.

The wavelength of the radiation emitted, when in a hydrogen atom an electron falls from infinity to stationary state 1, would be (Rydberg constant R = 1.097 \times 1 0^{7} m^{- 1}):

91 nm

9.1 \times 1 0^{- 8} nm

406 nm

192 nm

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