The x and y coordinates of the particle at any time are x = 5t - 2t^2 and y = 10t . The acceleration of the particle at t = 2 s is: - Physics MCQ NEET (UG) 2017 2026 | ExamTest.live

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The x and y coordinates of the particle at any time are x = 5 t - 2 t^{2} and y = 10 t . The acceleration of the particle at t = 2 s is:

Solution & Step-by-step Explanation

x = 5 t - 2 t^{2} ⟹ v_{x} = \frac{d x}{d t} = 5 - 4 t ⟹ a_{x} = \frac{d v _{x}}{d t} = - 4 m/s^{2} . y = 10 t ⟹ v_{y} = \frac{d y}{d t} = 10 ⟹ a_{y} = \frac{d v _{y}}{d t} = 0 .The net acceleration is a = a_{x} \hat{i} + a_{y} \hat{j} = - 4 \hat{i} + 0 \hat{j} .The magnitude is 4 m/s^{2} in the negative x direction.

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The x and y coordinates of the particle at any time are x = 5 t - 2 t^{2} and y = 10 t . The acceleration of the particle at t = 2 s is:

5 m/s^{2}

- 4 m/s^{2}

- 8 m/s^{2}

0

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