There are two urns. Urn A has 3 distinct red balls and urn B has 9 distinct blue balls. From each urn two balls are taken out at random and then trans - Mathematics MCQ AIEEE 2026 | ExamTest.live

mediumMCQAIEEE2026Mathematics

1 mark

There are two urns. Urn A has 3 distinct red balls and urn B has 9 distinct blue balls. From each urn two balls are taken out at random and then transferred to the other. The number of ways in which this can be done is:

Solution & Step-by-step Explanation

Ways to choose 2 red balls from Urn A = (2 3) = 3 .Ways to choose 2 blue balls from Urn B = (2 9) = \frac{9 \times 8}{2} = 36 .Since these are independent actions performed together, the total number of ways is the product:Total ways = 3 \times 36 = 108 .

Try it yourself before checking the explanation above.

There are two urns. Urn A has 3 distinct red balls and urn B has 9 distinct blue balls. From each urn two balls are taken out at random and then transferred to the other. The number of ways in which this can be done is:

36

66

108

3

Practice with timed mock tests and track your performance across Mathematics.