Through the publicity of road safety programmes, the street accidents in a state have decreased by 10\% in com

Question

Through the publicity of road safety programmes, the street accidents in a state have decreased by 10\% in comparison to its previous year. In the present year, if the number of street accidents is 2187 , the number of street accidents that had been in the state 3 years before was:

Accepted Answer

Let the number of street accidents in the state

3

years before be

P

.
The rate of decrease per year is

R = 10%

.
The number of accidents in the present year (

A

) is given by the formula:

A = P \times (1 - \frac{R}{100})^{n}

Given that

A = 2187

and

n = 3

:

2187 = P \times (1 - \frac{10}{100})^{3}

2187 = P \times (\frac{9}{10})^{3}

2187 = P \times \frac{729}{1000}

P = \frac{2187 \times 1000}{729}

P = 3 \times 1000 = 3000

Thus, the number of street accidents

3

years before was

3000

.

Through the publicity of road safety programmes, the street accidents in a state have decreased by $10%$ in comparison to its previous year. In the present year, if the number of street accidents is $2187$ , the number of street accidents that had been in the state $3$ years before was:

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Through the publicity of road safety programmes, the street accidents in a state have decreased by 10% in comparison to its previous year. In the present year, if the number of street accidents is 2187, the number of street accidents that had been in the state 3 years before was: