Through the publicity of road safety programmes, the street accidents in a state have decreased by 10\% in comparison to its previous year. In the pre - Quantitative Aptitude MCQ Competitive Examination 2026 | ExamTest.live

mediumMCQCompetitive Examination2026Quantitative Aptitude

1 mark

Through the publicity of road safety programmes, the street accidents in a state have decreased by 10% in comparison to its previous year. In the present year, if the number of street accidents is 2187, the number of street accidents that had been in the state 3 years before is:

Solution & Step-by-step Explanation

Let the number of accidents 3 years before be P . The rate of decrease is 10% annually. The population of accidents after 3 years is given by the formula for compound depreciation: A = P (1 - \frac{R}{100})^{n} Given A = 2187, R = 10, and n = 3 : 2187 = P (1 - \frac{10}{100})^{3} 2187 = P (\frac{9}{10})^{3} 2187 = P \times \frac{729}{1000} P = \frac{2187 \times 1000}{729} Since 729 \times 3 = 2187 : P = 3 \times 1000 = 3000 Thus, there were 3000 accidents three years ago.

Try it yourself before checking the explanation above.

Through the publicity of road safety programmes, the street accidents in a state have decreased by 10% in comparison to its previous year. In the present year, if the number of street accidents is 2187, the number of street accidents that had been in the state 3 years before is:

4000

2430

3000

1458

Practice with timed mock tests and track your performance across Quantitative Aptitude.