Today is 1st April. The day of the week is Wednesday. This is a leap year. The day of the week on this day after 3 years will be:

Let the current leap year be Year 0. We need to find the day on 1st April after 3 years.Since 1st April comes after February, the extra leap day of Year 0 has already passed.Let's look at the subsequent years:Year 1 (Non-leap year): $+1$ odd dayYear 2 (Non-leap year): $+1$ odd dayYear 3 (Non-leap year): $+1$ odd dayTotal odd days across 3 years = $1+1+1=3$ odd days.
$$\text{Day after 3 years}=\text{Wednesday}+3\text{ days}=\text{Saturday}$$