Two aeroplanes I and II bomb a target in succession. The probabilities of I and II scoring a hit correctly are 0.3 and 0.2 , respectively. The second - Mathematics MCQ AIEEE 2007 2026 | ExamTest.live

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Two aeroplanes I and II bomb a target in succession. The probabilities of I and II scoring a hit correctly are 0.3 and 0.2, respectively. The second plane will bomb only if the first misses the target. The probability that the target is hit by the second plane is:

Solution & Step-by-step Explanation

Let H_{1} be the event that plane I hits the target, P (H_{1}) = 0.3 .Let H_{2} be the event that plane II hits the target, P (H_{2}) = 0.2 .The second plane bombs only if the first plane misses.So, the target is hit by the second plane if the first plane misses and the second plane hits. P (Hit by II) = P (I misses) \times P (II hits) P (Hit by II) = (1 - 0.3) \times 0.2 P (Hit by II) = 0.7 \times 0.2 = 0.14

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Two aeroplanes I and II bomb a target in succession. The probabilities of I and II scoring a hit correctly are 0.3 and 0.2, respectively. The second plane will bomb only if the first misses the target. The probability that the target is hit by the second plane is:

0.06

0.14

0.2

0.7

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