Two bodies A and B of same mass undergo completely inelastic one dimensional collision. The body A moves with velocity v_1 while body B is at rest bef - Physics MCQ NEET (UG) 2024 2026 | ExamTest.live

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Two bodies A and B of same mass undergo completely inelastic one dimensional collision. The body A moves with velocity v_{1} while body B is at rest before collision. The velocity of the system after collision is v_{2} . The ratio v_{1} : v_{2} is:

Solution & Step-by-step Explanation

By conservation of linear momentum: m_{A} v_{1} + m_{B} (0) = (m_{A} + m_{B}) v_{2} Since masses are same (m_{A} = m_{B} = m): m v_{1} = (m + m) v_{2} m v_{1} = 2 m v_{2} \Rightarrow v_{1} = 2 v_{2} The ratio \frac{v _{1}}{v _{2}} = \frac{2}{1} .

Try it yourself before checking the explanation above.

Two bodies A and B of same mass undergo completely inelastic one dimensional collision. The body A moves with velocity v_{1} while body B is at rest before collision. The velocity of the system after collision is v_{2} . The ratio v_{1} : v_{2} is:

1 : 2

2 : 1

4 : 1

1 : 4

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