Two bodies of mass m and 9m are placed at a distance R . The gravitational potential on the line joining the bodies where the gravitational field equa - Physics MCQ NEET 2023 2026 | ExamTest.live

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Two bodies of mass m and 9 m are placed at a distance R . The gravitational potential on the line joining the bodies where the gravitational field equals zero, will be (G = gravitational constant):

Solution & Step-by-step Explanation

Let the field be zero at distance x from mass m . \frac{G m}{x ^{2}} = \frac{G ( 9 m )}{( R - x ) ^{2}} ⟹ \frac{1}{x} = \frac{3}{R - x} ⟹ R - x = 3 x ⟹ x = \frac{R}{4} Distance from 9 m is R - R /4 = 3 R /4 .Gravitational potential V at this point: V = - \frac{G m}{R /4} - \frac{G ( 9 m )}{3 R /4} V = - \frac{4 G m}{R} - \frac{36 G m}{3 R} = - \frac{4 G m}{R} - \frac{12 G m}{R} V = - \frac{16 G m}{R}

Try it yourself before checking the explanation above.

Two bodies of mass m and 9 m are placed at a distance R . The gravitational potential on the line joining the bodies where the gravitational field equals zero, will be (G = gravitational constant):

- \frac{8 G m}{R}

- \frac{12 G m}{R}

- \frac{16 G m}{R}

- \frac{20 G m}{R}

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