Two boys are standing at the ends A and B of a ground, where AB = a. The boy at B starts running in a direction perpendicular to AB with velocity v1. The boy at A starts running simultaneously with velocity v and catches the other boy in a time t, where t is :
- Aa/√(v2 + v21)
- B√(a/v2 - v21)
- Ca/(v - v1)
- Da/(v + v1)