Two bullets are fired horizontally and simultaneously towards each other from the rooftops of two buildings (building distance being 200 m apart and b - PHYSICS MCQ NEET 2019 2026 | ExamTest.live

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Two bullets are fired horizontally and simultaneously towards each other from the rooftops of two buildings (building distance being 200 m apart and being of the same height of 200 m) with the same velocity of 25 m/s . When and where will the two bullets collide? (g = 10 m/s^{2})

Solution & Step-by-step Explanation

Relative horizontal velocity v_{re l} = v_{1} - (- v_{2}) = 25 + 25 = 50 m/s .Time of collision t = \frac{Distance}{v _{re l}} = \frac{200}{50} = 4 s .Both bullets fall vertically with acceleration g from the same height.Vertical distance fallen in 4 s : y = \frac{1}{2} g t^{2} = \frac{1}{2} \times 10 \times 4^{2} = 80 m .Height from ground = Initial height - fallen distance = 200 - 80 = 120 m .

Try it yourself before checking the explanation above.

Two bullets are fired horizontally and simultaneously towards each other from the rooftops of two buildings (building distance being 200 m apart and being of the same height of 200 m) with the same velocity of 25 m/s . When and where will the two bullets collide? (g = 10 m/s^{2})

After 2 s at a height of 180 m

After 2 s at a height of 20 m

After 4 s at a height of 120 m

They will not collide.

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