Two buses cover the same distance moving at speeds of 40 km/h and 50 km/h, respectively. What is the distance covered by each of them (in km) if the slower bus takes one hour more than the faster bus?
- A200
- B225
- C216
- D210
Solution & Step-by-step Explanation
Let the distance covered by each bus be D km.
The speed of the slower bus (S
1
) = 40 km/h
The speed of the faster bus (S
2
) = 50 km/h
Time taken by the slower bus =
40
D
hours
Time taken by the faster bus =
50
D
hours
According to the question, the difference in time is 1 hour:
40
D
−
50
D
=1
Taking the LCM of 40 and 50, which is 200:
200
5D−4D
=1
200
D
=1
D=200 km
Thus, the distance covered by each bus is 200 km.
The speed of the slower bus (S
1
) = 40 km/h
The speed of the faster bus (S
2
) = 50 km/h
Time taken by the slower bus =
40
D
hours
Time taken by the faster bus =
50
D
hours
According to the question, the difference in time is 1 hour:
40
D
−
50
D
=1
Taking the LCM of 40 and 50, which is 200:
200
5D−4D
=1
200
D
=1
D=200 km
Thus, the distance covered by each bus is 200 km.