Two capacitors C_1 and C_2 are charged to 120 V and 200 V respectively. It is found that by connecting them together the potential on each one can be - Physics MCQ JEE Main 2026 | ExamTest.live | ExamTest.live

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Two capacitors C_{1} and C_{2} are charged to 120 V and 200 V respectively. It is found that by connecting them together the potential on each one can be made zero. Then:

A $3C_1 = 5C_2$
B $3C_1 + 5C_2 = 0$
C $9C_1 = 4C_2$
D $5C_1 = 3C_2$

Solution & Step-by-step Explanation

For the potential to become zero, the total charge on the system must be zero. This happens if the capacitors are connected with opposite polarities. Q_{1} = C_{1} V_{1} = 120 C_{1} Q_{2} = C_{2} V_{2} = 200 C_{2} For Q_{t o t a l} = 0 : 120 C_{1} = 200 C_{2} \Rightarrow 12 C_{1} = 20 C_{2} \Rightarrow 3 C_{1} = 5 C_{2} .

Practice this question

Try it yourself before checking the explanation above.

Two capacitors C_{1} and C_{2} are charged to 120 V and 200 V respectively. It is found that by connecting them together the potential on each one can be made zero. Then:

A

3C_1 = 5C_2

B

3C_1 + 5C_2 = 0

C

9C_1 = 4C_2

D

5C_1 = 3C_2

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Electromagnetism Electrostatics Capacitors

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