Two cars travel from city A to city B at a speed of 60 and 108 km/hr respectively. If one car takes 2 hours lesser time than the other car for the journey, then the distance between City A and City B?
- A270 km
- B324 km
- C405 km
- D216 km
Solution & Step-by-step Explanation
Let the distance between City A and City B be d km.
The time taken by the first car (speed = 60 km/hr) is:
t
1
=
60
d
The time taken by the second car (speed = 108 km/hr) is:
t
2
=
108
d
According to the question, the difference between their travel times is 2 hours:
t
1
−t
2
=2
60
d
−
108
d
=2
Find the LCM of 60 and 108, which is 540:
540
9d−5d
=2
540
4d
=2
4d=1080
d=
4
1080
=270 km
Thus, the distance between City A and City B is 270 km.
The time taken by the first car (speed = 60 km/hr) is:
t
1
=
60
d
The time taken by the second car (speed = 108 km/hr) is:
t
2
=
108
d
According to the question, the difference between their travel times is 2 hours:
t
1
−t
2
=2
60
d
−
108
d
=2
Find the LCM of 60 and 108, which is 540:
540
9d−5d
=2
540
4d
=2
4d=1080
d=
4
1080
=270 km
Thus, the distance between City A and City B is 270 km.