Two cars travel from city A to city B at a speed of 30km/hr and 48km/hr respectively. If one car takes 3 hours lesser time than the other car for the journey, then the distance between City A and City B is:

Let the distance between City A and City B be dkm.
The speed of the first car is v
1
​
=30km/hr and the speed of the second car is v
2
​
=48km/hr.

The time taken by the first car is:

t
1
​
=
30
d
​

The time taken by the second car is:

t
2
​
=
48
d
​

According to the question, the difference in time taken by the two cars is 3 hours:

t
1
​
−t
2
​
=3
30
d
​
−
48
d
​
=3
Taking the LCM of 30 and 48, which is 240:

240
8d−5d
​
=3
240
3d
​
=3
80
d
​
=3
d=240km
Therefore, the distance between City A and City B is 240km.