Two cars travel from city A to city B at a speed of 30 and 44km/hr respectively. If one car takes 3.5 hours lesser time than the other car for the journey, then the distance between City A and City B is:
- A330km
- B396km
- C495km
- D264km
Solution & Step-by-step Explanation
Let the distance between City A and City B be dkm.
Time taken by the slower car (t
1
) =
30
d
hours.
Time taken by the faster car (t
2
) =
44
d
hours.
Given the difference in time is 3.5 hours (which is
2
7
hours):
30
d
−
44
d
=3.5
Find the LCM of 30 and 44, which is 660:
660
22d−15d
=
2
7
660
7d
=
2
7
Divide both sides by 7:
660
d
=
2
1
d=
2
660
=330km
Time taken by the slower car (t
1
) =
30
d
hours.
Time taken by the faster car (t
2
) =
44
d
hours.
Given the difference in time is 3.5 hours (which is
2
7
hours):
30
d
−
44
d
=3.5
Find the LCM of 30 and 44, which is 660:
660
22d−15d
=
2
7
660
7d
=
2
7
Divide both sides by 7:
660
d
=
2
1
d=
2
660
=330km