Two cars travel from city A to city B at a speed of 48km/hr and 60km/hr respectively. If one car takes 3.5 hours lesser time than the other car for the journey, then the distance between City A and City B is:
- A1008km
- B1260km
- C840km
- D672km
Solution & Step-by-step Explanation
Let the distance between City A and City B be Dkm.
Time taken by the slower car =
48
D
Time taken by the faster car =
60
D
Given that the difference in time is 3.5 hours:
48
D
−
60
D
=3.5
LCM of 48 and 60 is 240.
240
5D−4D
=3.5
240
D
=3.5
D=3.5×240=840km
Time taken by the slower car =
48
D
Time taken by the faster car =
60
D
Given that the difference in time is 3.5 hours:
48
D
−
60
D
=3.5
LCM of 48 and 60 is 240.
240
5D−4D
=3.5
240
D
=3.5
D=3.5×240=840km