Two cars travel from city A to city B at a speed of 30km/hr and 36km/hr respectively. If one car takes 3 hours lesser time than the other car for the journey, then the distance between City A and City B is:
- A648km
- B810km
- C432km
- D540km
Solution & Step-by-step Explanation
Let the distance between City A and City B be Dkm.
Time taken by the first car (t
1
) =
30
D
hours
Time taken by the second car (t
2
) =
36
D
hours
The difference between their travel times is 3 hours:
t
1
−t
2
=3
30
D
−
36
D
=3
Taking the LCM of 30 and 36, which is 180:
180
6D−5D
=3
180
D
=3
D=3×180=540km
Thus, the distance between City A and City B is 540km.
Time taken by the first car (t
1
) =
30
D
hours
Time taken by the second car (t
2
) =
36
D
hours
The difference between their travel times is 3 hours:
t
1
−t
2
=3
30
D
−
36
D
=3
Taking the LCM of 30 and 36, which is 180:
180
6D−5D
=3
180
D
=3
D=3×180=540km
Thus, the distance between City A and City B is 540km.