Two cars travel from city A to city B at a speed of 36 and 54km/hr respectively. If one car takes 3.5 hours lesser time than the other car for the journey, then the distance between City A and City B is:
- A454 km
- B567 km
- C302 km
- D378 km
Solution & Step-by-step Explanation
Let the distance between City A and City B be d km.
The speed of the first car (s
1
) = 36km/hr
The speed of the second car (s
2
) = 54km/hr
Time taken by the first car (t
1
) =
36
d
hours
Time taken by the second car (t
2
) =
54
d
hours
Given that the faster car takes 3.5 hours less time:
t
1
−t
2
=3.5
36
d
−
54
d
=3.5
Taking LCM of 36 and 54, which is 108:
108
3d−2d
=3.5
108
d
=3.5
d=3.5×108
d=378km
The speed of the first car (s
1
) = 36km/hr
The speed of the second car (s
2
) = 54km/hr
Time taken by the first car (t
1
) =
36
d
hours
Time taken by the second car (t
2
) =
54
d
hours
Given that the faster car takes 3.5 hours less time:
t
1
−t
2
=3.5
36
d
−
54
d
=3.5
Taking LCM of 36 and 54, which is 108:
108
3d−2d
=3.5
108
d
=3.5
d=3.5×108
d=378km