Two fixed frictionless inclined planes making an angle 30^ and 60^ with the vertical are shown. Two blocks A and B are placed on the two planes. What - Physics MCQ AIEEE 2026 | ExamTest.live

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Two fixed frictionless inclined planes making an angle 3 0^{\circ} and 6 0^{\circ} with the vertical are shown. Two blocks A and B are placed on the two planes. What is the relative vertical acceleration of A with respect to B ?

Solution & Step-by-step Explanation

Let the angle with the horizontal be α .For plane A, angle with vertical is 3 0^{\circ}, so α_{A} = 6 0^{\circ} .For plane B, angle with vertical is 6 0^{\circ}, so α_{B} = 3 0^{\circ} .Acceleration along the plane a = g sin α .Vertical component of acceleration a_{v} = a sin α = g sin^{2} α . a_{v A} = g sin^{2} 6 0^{\circ} = g (\frac{3}{2})^{2} = \frac{3 g}{4} . a_{v B} = g sin^{2} 3 0^{\circ} = g (\frac{1}{2})^{2} = \frac{g}{4} .Relative vertical acceleration = ∣ a_{v A} - a_{v B} ∣ = \frac{3 g}{4} - \frac{g}{4} = \frac{g}{2} = \frac{9.8}{2} = 4.9 m s^{- 2} .

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Two fixed frictionless inclined planes making an angle 3 0^{\circ} and 6 0^{\circ} with the vertical are shown. Two blocks A and B are placed on the two planes. What is the relative vertical acceleration of A with respect to B ?

4.9 m s^{- 2} in horizontal direction

9.8 m s^{- 2} in vertical direction

zero

4.9 m s^{- 2} in vertical direction

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