Two full turns of a screw gauge cover 1 mm . Total divisions on circular scale is 50 . Zero error is -0.03 mm . While measuring, main scale reading is - Physics MCQ AIEEE 2026 | ExamTest.live

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1 mark

Two full turns of a screw gauge cover 1 mm . Total divisions on circular scale is 50 . Zero error is - 0.03 mm . While measuring, main scale reading is 3 mm and circular scale is 35 . The diameter of the wire is:

Solution & Step-by-step Explanation

Pitch = 1 mm /2 = 0.5 mm .Least Count (L.C.) = Pitch / Divisions = 0.5/50 = 0.01 mm .Measured Reading = M.S.R. + (C.S.R. \times L.C.) = 3 + (35 \times 0.01) = 3.35 mm .True Reading = Measured Reading - Zero Error = 3.35 - (- 0.03) = 3.38 mm .

Try it yourself before checking the explanation above.

Two full turns of a screw gauge cover 1 mm . Total divisions on circular scale is 50 . Zero error is - 0.03 mm . While measuring, main scale reading is 3 mm and circular scale is 35 . The diameter of the wire is:

3.32 mm

3.73 mm

3.67 mm

3.38 mm

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