Two numbers X and Y are respectively 20\% and 28\% less than a third number Z . By what percentage is the number Y less than the number X ? - Mathematics MCQ Competitive Exam 2026 | ExamTest.live

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Two numbers X and Y are respectively 20% and 28% less than a third number Z . By what percentage is the number Y less than the number X ?

Solution & Step-by-step Explanation

Let the third number Z be equal to 100 . * X is 20% less than Z ⟹ X = 100 - 20 = 80 * Y is 28% less than Z ⟹ Y = 100 - 28 = 72 We need to find by what percentage Y is less than X : Difference = X - Y = 80 - 72 = 8 Required Percentage = \frac{Difference}{X} \times 100 Required Percentage = \frac{8}{80} \times 100 = 10%

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Two numbers X and Y are respectively 20% and 28% less than a third number Z . By what percentage is the number Y less than the number X ?

8%

12%

10%

9%

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