Two particles A and B of equal masses are suspended from two massless springs of spring constants k_1 and k_2 respectively. If the maximum velocities - Physics MCQ AIEEE 2003 2026 | ExamTest.live

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Two particles A and B of equal masses are suspended from two massless springs of spring constants k_{1} and k_{2} respectively. If the maximum velocities during oscillations are equal, the ratio of amplitudes of A and B is:

Solution & Step-by-step Explanation

Maximum velocity in SHM is v_{ma x} = A ω .Given v_{ma x, A} = v_{ma x, B} : A_{1} ω_{1} = A_{2} ω_{2} ω = \frac{k}{m} Since masses are equal: A_{1} \frac{k _{1}}{m} = A_{2} \frac{k _{2}}{m} \frac{A _{1}}{A _{2}} = \frac{k _{2}}{k _{1}}

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Two particles A and B of equal masses are suspended from two massless springs of spring constants k_{1} and k_{2} respectively. If the maximum velocities during oscillations are equal, the ratio of amplitudes of A and B is:

\frac{k _{1}}{k _{2}}

\frac{k _{2}}{k _{1}}

\frac{k _{2}}{k _{1}}

\frac{k _{1}}{k _{2}}

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