Two resistors of resistances, 100 Ω and 200 Ω are connected in parallel in an electrical circuit. The ratio of thermal energy developed in 100 Ω to th - Physics MCQ NEET 2022 2026 | ExamTest.live

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Two resistors of resistances, 100 Ω and 200 Ω are connected in parallel in an electrical circuit. The ratio of thermal energy developed in 100 Ω to that in 200 Ω in a given time is:

Solution & Step-by-step Explanation

For resistors in parallel, the potential difference V across them is the same.Thermal energy H = \frac{V ^{2}}{R} t .Since V and t are constant: H \propto \frac{1}{R} \frac{H _{1}}{H _{2}} = \frac{R _{2}}{R _{1}} = \frac{200}{100} = \frac{2}{1} The ratio is 2 : 1 .

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Two resistors of resistances, 100 Ω and 200 Ω are connected in parallel in an electrical circuit. The ratio of thermal energy developed in 100 Ω to that in 200 Ω in a given time is:

1 : 2

2 : 1

1 : 4

4 : 1

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