Two rods A and B of same length and area but different materials are joined in parallel. Their thermal conductivities are K_1 and K_2 . The thermal co - Physics MCQ NEET (UG) 2017 2026 | ExamTest.live

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Two rods A and B of same length and area but different materials are joined in parallel. Their thermal conductivities are K_{1} and K_{2} . The thermal conductivity of the composite rod will be:

Solution & Step-by-step Explanation

For parallel combination:Equivalent conductivity K_{eq} = \frac{K _{1} A _{1} + K _{2} A _{2}}{A _{1} + A _{2}} Since areas are same (A_{1} = A_{2} = A): K_{eq} = \frac{K _{1} A + K _{2} A}{2 A} = \frac{K _{1} + K _{2}}{2} (Note: Question implies a parallel set-up based on the 2017 paper context).

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Two rods A and B of same length and area but different materials are joined in parallel. Their thermal conductivities are K_{1} and K_{2} . The thermal conductivity of the composite rod will be:

\frac{K _{1} + K _{2}}{2}

K_{1} + K_{2}

2 (K_{1} + K_{2})

\frac{K _{1} K _{2}}{K _{1} + K _{2}}

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