Two solutions of a substance (non-electrolyte) are mixed in the following manner: 480 mL of 1.5 M first solution + 520 mL of 1.2 M second solution. Wh - Chemistry MCQ AIEEE 2026 | ExamTest.live

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Two solutions of a substance (non-electrolyte) are mixed in the following manner: 480 mL of 1.5 M first solution + 520 mL of 1.2 M second solution. What is the molarity of the final mixture?

Solution & Step-by-step Explanation

The molarity of a mixture (M_{mi x}) is given by: M_{mi x} = \frac{M _{1} V _{1} + M _{2} V _{2}}{V _{1} + V _{2}} Calculation: M_{mi x} = \frac{( 1.5 \times 480 ) + ( 1.2 \times 520 )}{480 + 520} M_{mi x} = \frac{720 + 624}{1000} = \frac{1344}{1000} = 1.344 M

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Two solutions of a substance (non-electrolyte) are mixed in the following manner: 480 mL of 1.5 M first solution + 520 mL of 1.2 M second solution. What is the molarity of the final mixture?

1.20 M

1.50 M

1.344 M

2.70 M

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