Two toroids 1 and 2 have total no. of turns 200 and 100 respectively with average radii 40 cm and 20 cm respectively. If they carry the same current i - PHYSICS MCQ NEET 2019 2026 | ExamTest.live

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Two toroids 1 and 2 have total no. of turns 200 and 100 respectively with average radii 40 cm and 20 cm respectively. If they carry the same current i, what will be the ratio of the magnetic fields along the two loops?

Solution & Step-by-step Explanation

The magnetic field inside a toroid is B = μ_{0} ni, where n = \frac{N}{2 π R} .So, B \propto \frac{N}{R} .Ratio: \frac{B _{1}}{B _{2}} = \frac{N _{1} / R _{1}}{N _{2} / R _{2}} = \frac{N _{1}}{R _{1}} \times \frac{R _{2}}{N _{2}} \frac{B _{1}}{B _{2}} = \frac{200}{40} \times \frac{20}{100} = 5 \times 0.2 = 1 .So the ratio is 1 : 1 .

Try it yourself before checking the explanation above.

Two toroids 1 and 2 have total no. of turns 200 and 100 respectively with average radii 40 cm and 20 cm respectively. If they carry the same current i, what will be the ratio of the magnetic fields along the two loops?

1 : 1

4 : 1

2 : 1

1 : 2

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