Two trains A and B start at uniform speeds, simultaneously from two stations P and Q, respectively, towards each other. After crossing each other, A takes 20 hours to reach Q and B takes 5 hours to reach P. If train A is moving at a speed of 55 km/h, the speed of B (in km/h) is:
- A112
- B100
- C110
- D105
Solution & Step-by-step Explanation
Let the speed of train A be S
A
and the speed of train B be S
B
.
Let the time taken by A to reach its destination after crossing be T
A
, and by B be T
B
.
Given:
S
A
=55 km/h
T
A
=20 hours
T
B
=5 hours
We know the standard relation for two objects moving towards each other meeting and continuing to their destinations:
S
B
S
A
=
T
A
T
B
Substituting the given values:
S
B
55
=
20
5
S
B
55
=
4
1
S
B
55
=
2
1
S
B
=55×2=110 km/h
A
and the speed of train B be S
B
.
Let the time taken by A to reach its destination after crossing be T
A
, and by B be T
B
.
Given:
S
A
=55 km/h
T
A
=20 hours
T
B
=5 hours
We know the standard relation for two objects moving towards each other meeting and continuing to their destinations:
S
B
S
A
=
T
A
T
B
Substituting the given values:
S
B
55
=
20
5
S
B
55
=
4
1
S
B
55
=
2
1
S
B
=55×2=110 km/h