Under isothermal condition, a gas at 300K expands from 0.1L to 0.25L against a constant external pressure of 2bar. The work done by the gas is (Given that 1L bar=100J):
- A−30J
- B5kJ
- C25J
- D30J
Solution & Step-by-step Explanation
For expansion against a constant external pressure:
W=−P
ext
ΔV
Given P
ext
=2bar, V
i
=0.1L, and V
f
=0.25L.
W=−2×(0.25−0.1)=−2×0.15=−0.3L bar
Converting to Joules:
W=−0.3×100J=−30J
The negative sign indicates work is done by the gas.
W=−P
ext
ΔV
Given P
ext
=2bar, V
i
=0.1L, and V
f
=0.25L.
W=−2×(0.25−0.1)=−2×0.15=−0.3L bar
Converting to Joules:
W=−0.3×100J=−30J
The negative sign indicates work is done by the gas.