What is the difference between the compound interest on a sum of ₹10,000 at 12% p.a. for 1
4
1
years when the interest is compounded annually and when the interest is compounded 5-monthly? (nearest to a ₹)
- A35
- B40
- C36
- D42
Solution & Step-by-step Explanation
Given:
Principal (P) = ₹10,000
Rate (R) = 12% p.a.
Time (T) = 1
4
1
years=
4
5
years=
4
5
×12=15 months
Case 1: Compounded Annually
The time is 1 year 3 months.
Amount after 1st year = 10000×(1+
100
12
)=11200
Interest for the remaining 3 months (3/12=1/4 year) on ₹11,200:
Interest=11200×12%×
4
1
=11200×3%=336
Total Amount (A
1
) = 11200+336=11536
CI
1
=11536−10000=₹1,536
Case 2: Compounded 5-Monthly
Number of periods (n) =
5 months
15 months
=3 periods
Rate per 5 months (R
′
) = 12%×
12
5
=5% per period
Using the formula for the amount:
A
2
=10000×(1+
100
5
)
3
=10000×(1.05)
3
We know (1.05)
3
=1.157625.
A
2
=10000×1.157625=11576.25
CI
2
=11576.25−10000=₹1,576.25
Difference between the two interests:
Difference=CI
2
−CI
1
=1576.25−1536=40.25
Rounding to the nearest rupee gives ₹40.
Principal (P) = ₹10,000
Rate (R) = 12% p.a.
Time (T) = 1
4
1
years=
4
5
years=
4
5
×12=15 months
Case 1: Compounded Annually
The time is 1 year 3 months.
Amount after 1st year = 10000×(1+
100
12
)=11200
Interest for the remaining 3 months (3/12=1/4 year) on ₹11,200:
Interest=11200×12%×
4
1
=11200×3%=336
Total Amount (A
1
) = 11200+336=11536
CI
1
=11536−10000=₹1,536
Case 2: Compounded 5-Monthly
Number of periods (n) =
5 months
15 months
=3 periods
Rate per 5 months (R
′
) = 12%×
12
5
=5% per period
Using the formula for the amount:
A
2
=10000×(1+
100
5
)
3
=10000×(1.05)
3
We know (1.05)
3
=1.157625.
A
2
=10000×1.157625=11576.25
CI
2
=11576.25−10000=₹1,576.25
Difference between the two interests:
Difference=CI
2
−CI
1
=1576.25−1536=40.25
Rounding to the nearest rupee gives ₹40.