What is the least value of k, so that 23k57 is divisible by 3?
- A3
- B0
- C2
- D1
Solution & Step-by-step Explanation
A number is divisible by 3 if the sum of its digits is divisible by 3.
The given number is 23k57.
Sum of digits=2+3+k+5+7=17+k
For the number to be divisible by 3, (17+k) must be a multiple of 3.
The smallest multiple of 3 greater than or equal to 17 is 18.
Therefore:
17+k=18⟹k=1
Thus, the least value of k is 1.
The given number is 23k57.
Sum of digits=2+3+k+5+7=17+k
For the number to be divisible by 3, (17+k) must be a multiple of 3.
The smallest multiple of 3 greater than or equal to 17 is 18.
Therefore:
17+k=18⟹k=1
Thus, the least value of k is 1.