What is the perpendicular distance from the point $(2,3,4)$ to the line $\frac{x-0}{1}=\frac{y-0}{0}=\frac{z-0}{0}$?

The given line is $\frac{x}{1}=\frac{y}{0}=\frac{z}{0}$. This is the $x$ -axis.The point is $P(2,3,4)$.The foot of the perpendicular from $(2,3,4)$ on the $x$ -axis is $(2,0,0)$.The perpendicular distance is the distance between $(2,3,4)$ and $(2,0,0)$:
$$d=\sqrt{(2-2{)}^2+(3-0{)}^2+(4-0{)}^2}$$
$$d=\sqrt{0^2+3^2+4^2}=\sqrt{9+16}=\sqrt{25}=5\text{units}$$