What least number must be subtracted from 2001 to get a number exactly divisible by 17?
- A12
- B13
- C11
- D14
Solution & Step-by-step Explanation
To find the least number to subtract, we divide 2001 by 17 and find the remainder.
2001÷17
17×1=17, remainder =3. Bring down 0⟹30.
17×1=17, remainder =13. Bring down 1⟹131.
17×7=119.
Remainder=131−119=12
Since the remainder is 12, subtracting 12 from 2001 will leave a number perfectly divisible by 17.
2001÷17
17×1=17, remainder =3. Bring down 0⟹30.
17×1=17, remainder =13. Bring down 1⟹131.
17×7=119.
Remainder=131−119=12
Since the remainder is 12, subtracting 12 from 2001 will leave a number perfectly divisible by 17.