What smallest number should be added to 2957 so that the sum is completely divisible by 17?
- A9
- B2
- C3
- D1
Solution & Step-by-step Explanation
First, let us divide 2957 by 17 to find the remainder:
2957÷17
17×100=1700
2957−1700=1257
17×70=1190
1257−1190=67
17×3=51
Remainder=67−51=16
Since the remainder is 16, the number needed to be added to make it perfectly divisible by 17 is:
Number to be added=Divisor−Remainder
Number to be added=17−16=1
2957÷17
17×100=1700
2957−1700=1257
17×70=1190
1257−1190=67
17×3=51
Remainder=67−51=16
Since the remainder is 16, the number needed to be added to make it perfectly divisible by 17 is:
Number to be added=Divisor−Remainder
Number to be added=17−16=1