What will be the roots of the quadratic equation $x^2-25x+156=0$?

Given quadratic equation:
$$x^2-25x+156=0$$
We can solve this by splitting the middle term. We need two numbers whose sum is $-25$ and whose product is $156$.The numbers are $-12$ and $-13$:
$$x^2-12x-13x+156=0$$
$$x(x-12)-13(x-12)=0$$
$$(x-12)(x-13)=0$$
Therefore, the roots are:
$$x=12\text{and}x=13$$