When a system is taken from state i to state f along the path iaf , it is found that Q = 50 cal and W = 20 cal . Along the path ibf , Q = 36 cal . W along the path ibf is: ![image](https://pub-7faa453bd1ec4bf0a04cc031c6f058de.r2.dev/images/8116c973-9d69-4b92-aa8b-6b523b7b24fc.png)

When a system is taken from state i to state f along the path iaf , it is found that Q = 50 cal and W = 20 cal . Along the path ibf , Q = 36 cal . W a - Physics MCQ AIEEE 2007 2026 | ExamTest.live

mediumMCQAIEEE 20072026Physics

1 attempts0% success rate1 mark

When a system is taken from state i to state f along the path ia f, it is found that Q = 50 cal and W = 20 cal . Along the path ib f, Q = 36 cal . W along the path ib f is:

According to the First Law of Thermodynamics, Δ U = Q - W .The change in internal energy Δ U depends only on the initial and final states, not on the path.For path ia f : Δ U = Q_{ia f} - W_{ia f} = 50 - 20 = 30 cal For path ib f : Δ U = Q_{ib f} - W_{ib f} 30 = 36 - W_{ib f} W_{ib f} = 36 - 30 = 6 cal

Try it yourself before checking the explanation above.

When a system is taken from state i to state f along the path ia f, it is found that Q = 50 cal and W = 20 cal . Along the path ib f, Q = 36 cal . W along the path ib f is:

6 cal

16 cal

66 cal

14 cal

Practice with timed mock tests and track your performance across Physics.