Which among the following will be named as dibromidobis(ethylenediamine)chromium(III) bromide?

Breakdown of the name:Dibromido: Two ${\text{Br}}^{-}$ ligands inside the coordination sphere.Bis(ethylenediamine): Two 'en' ligands inside.Chromium(III): Central metal ion is $\text{Cr}$ with oxidation state $+3$.Bromide: ${\text{Br}}^{-}$ ion outside the sphere.Formula construction: $[\text{Cr}(\text{en}{)}_2{\text{Br}}_2{]}^x{\text{Br}}_y$.Charge calculation: $\text{Cr}(+3)+2\times \text{en}(0)+2\times \text{Br}(-1)=+1$.So the complex ion is $[\text{Cr}(\text{en}{)}_2{\text{Br}}_2{]}^{+}$.To neutralize this, one ${\text{Br}}^{-}$ is needed outside.Formula: $[\text{Cr}(\text{en}{)}_2{\text{Br}}_2]\text{Br}$.