Which letter-cluster will replace the question mark (?) to complete the given series?
ETGW, ?, INOM, KKSH, MHWC
- AGRKS
- BGQKR
- CHQLR
- DHRLS
Solution & Step-by-step Explanation
Let's break down the sequence by investigating the transformation of each letter position:
1st letter: E (5) → G (7) → I (9) → K (11) → M (13) [+2 steps]
2nd letter: T (20) → R (18) → N (14) → K (11) → H (8)
Let's check differences: 20−2=18 (R), 18−4=14 (N), 14−3=11 (K), 11−3=8 (H). This looks non-uniform. Let's re-examine standard option keys:
If pattern is constant −2 then: T(20) → R(18) → P(16). But next letter is INOM.
Let's re-verify positional values: T(20), R(18), N(14), K(11), H(8). The pattern of differences is −2,−4,−3,−3 which is unusual.
Let's check option GQKR: If 2nd letter is Q (17), then sequence is T(20) → Q(17) → N(14) → K(11) → H(8). This is a uniform sequence of −3 steps!
3rd letter: G (7) → K (11) → O (15) → S (19) → W (23) [+4 steps]
4th letter: W (23) → R (18) → M (13) → H (8) → C (3) [-5 steps]
Matching the verified patterns:
1st letter: 5+2=7→ G
2nd letter: 20−3=17→ Q
3rd letter: 7+4=11→ K
4th letter: 23−5=18→ R
Hence, the missing cluster is GQKR.
1st letter: E (5) → G (7) → I (9) → K (11) → M (13) [+2 steps]
2nd letter: T (20) → R (18) → N (14) → K (11) → H (8)
Let's check differences: 20−2=18 (R), 18−4=14 (N), 14−3=11 (K), 11−3=8 (H). This looks non-uniform. Let's re-examine standard option keys:
If pattern is constant −2 then: T(20) → R(18) → P(16). But next letter is INOM.
Let's re-verify positional values: T(20), R(18), N(14), K(11), H(8). The pattern of differences is −2,−4,−3,−3 which is unusual.
Let's check option GQKR: If 2nd letter is Q (17), then sequence is T(20) → Q(17) → N(14) → K(11) → H(8). This is a uniform sequence of −3 steps!
3rd letter: G (7) → K (11) → O (15) → S (19) → W (23) [+4 steps]
4th letter: W (23) → R (18) → M (13) → H (8) → C (3) [-5 steps]
Matching the verified patterns:
1st letter: 5+2=7→ G
2nd letter: 20−3=17→ Q
3rd letter: 7+4=11→ K
4th letter: 23−5=18→ R
Hence, the missing cluster is GQKR.